Question

The price of carrot is twise that of patatoes . Raj brought 3kg correct and 2 kg potato 160 find the per kg price of carrot and potatoes

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\bf{\large{\underline{\underline{\sf{Answer:}}}}}$

$\bf{\large{\underline{\rm{Per\:kg\: price\: of\: potato\: =\: Rs\:.\:20}}}}$

$\bf{\large{\underline{\rm{Per\:kg\: price\: of\:carrot\: =\: Rs\:.\:40}}}}$

$\bf{\large{\underline{\underline{\sf{Explaination:}}}}}$

$\bf{\underline{\underline{\sf{Given:}}}}$

• Price of carrots is twice that of potatoes.
• Raj brought 3 kg carrot and 2 kg potatoes for ₹ 160

$\bf{\underline{\underline{\sf{To\:find:}}}}$

• Per kg price of carrot
• Per kg price of potatoes

$\bf{\underline{\underline{\sf{Solution:}}}}$

Let the per kg price of carrot be ₹ x

Let the per kg price of potato be ₹ y

$\bf{\underline{\underline{\sf{As\:per\:the\:question:}}}}$

$\bf{\underline{\rm{Price\: of\:carrots\: is \:twice \:that\:of\:potatoes\:}}}$

•°• x = 2y ----> (1)

$\bf{\underline{\rm{Raj\: brought\:3\:kg\:carrot\:and\:2\: kg\:potatoes\: for\:Rs\:.\:160}}}$

=> 3x + 2y = 160 ----> (2)

Substitute x = 2y in equation 2 for 3x,

=> 3 ( 2y) + 2y = 160

=> 6y + 2y = 160

=> 8y = 160

=> y = $\bf\large\frac{\cancel{160}}{\cancel{8}}$

=> y = 20

Substitute y = 20 in equation 2,

=> 3x + 2y =160

=> 3x + 2 (20) = 160

=> 3x + 40 = 160

=> 3x = 160 - 40

=> 3x = 120

=> x = $\bf\large\frac{\cancel{120}}{\cancel{3}}$

=> x = 40