The price of one box is (a-7)Rs. what is the tolhe cost of (a+7) boxes?
Answers
Step-by-step explanation:
Here, as per the given question we are given that the price of one book is Rs. (a - 7). And now we have to find the total cost of (a + 7) boxes. If the the price of one book is Rs. (a - 7) then the cost of (a + 7) boxes will be cost of 1 box times the number of the boxes. Basically, we'll multiply cost of one box with the number of the boxes to find the total cost of (a + 7) boxes.
\underline{ \underline{ \Large \pmb{\mathit{ {Given:}} }} }
Given:
Given:
• Cost of one book = Rs. (a - 7)
\underline{ \underline{ \Large \pmb{\mathit{ {To \: calculate:}} }} }
Tocalculate:
Tocalculate:
• Total cost of (a + 7) boxes.
\underline{ \underline{ \Large \pmb{\mathit{ {Calculation:}} }} }
Calculation:
Calculation:
If the cost of one box is (a - 7) then the cost of (a + 7) boxes will be the product of number of boxes and cost of 1 box.
\begin{gathered} \longrightarrow \sf { Cost_{(1 \: Box)} = Rs. \: (a-7) } \\\end{gathered}
⟶Cost
(1Box)
=Rs.(a−7)
\begin{gathered} \longrightarrow \sf { Total \: cost = Rs. \: Cost_{(1 \: Box)} \times (a+7) }\\\end{gathered}
⟶Totalcost=Rs.Cost
(1Box)
×(a+7)
\begin{gathered} \longrightarrow \sf { Total \: cost = Rs. \: (a-7) \times (a+7) }\\\end{gathered}
⟶Totalcost=Rs.(a−7)×(a+7)
\begin{gathered} \longrightarrow \sf { Cost_{[(a + 7) \: Boxes]} = Rs. \: (a-7)(a+7) } \\\end{gathered}
⟶Cost
[(a+7)Boxes]
=Rs.(a−7)(a+7)
By using identity,
\begin{gathered}\bigstar \: \boxed{\sf { (a-b)(a+b) ={a}^{2} - {b}^{2} }} \\ \end{gathered}
★
(a−b)(a+b)=a
2
−b
2
\begin{gathered} \longrightarrow \sf { Total \: cost = Rs. \: {(a)}^{2} - {(7)}^{2}}\\\end{gathered}
⟶Totalcost=Rs.(a)
2
−(7)
2
\begin{gathered} \longrightarrow \boxed { \pmb {\rm \red{ Total \: cost= Rs. \: {a}^{2} - 49}} } \\ \end{gathered}
⟶
Totalcost=Rs.a
2
−49
Totalcost=Rs.a
2
−49
Therefore, cost of (a + 7) boxes is Rs. a² - 49.
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Rs. a² - 49
answer
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