Question

The price of two articles are in the ratio 4:3.If the difference between the cost of the two articles is ₹42.50,then the price of the dearer article is?

Answer 1

Step-by-step explanation:

Let price of two articles are 3x and 4x

After increment price become 3.3x and (4x+4)

Now, according to question,

3.3x/4x+4=3/4

13.2x=12x+1

13.2x−12x=12

1.2x=12

x=10

So, original price of second article =4x=4×10=Rs 40.