Math, asked by dhanbirkumar714, 6 months ago

The price of two computers is * 12000. The prices are in the ratio 4 : 6. How
much does each computer cost?​

Answers

Answered by Anonymous
3

Step-by-step explanation:

let the price of two computer be :

4x and 6x

According to the situation,

4x + 5x =12000

9x = 12000

x.= 12000/ 9

x= 1,333.3333.......

so, 1 st computer= 4× 1333.3....

= rs 5333.2...

2nd computer = 6 × 1333.3.....

= rs 7999.8....

I hope u have got it........

Answered by SofiaDCruz
1

Step-by-step explanation:

Let the price of 1st computer be 4x and the price of 2nd computer be 6x respectively.

According to the question,

4x + 6x = ₹12000

=> 10x = ₹12000

=> x = ₹12000/10

=> x = ₹1200

Therefore,

Cost of 1st computer = 4x

= 4*₹1200

= ₹4800 ; and

Cost of 2nd computer = 6x

= 6*₹1200

= ₹7200

Hope it helps...

Thank You

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