the price of two oranges, three bananas and four apples is Rs.15. And the price of three oranges, two bananas and one apple is Rs.10. therefore the price of 3oranges, 3banana and 3apple
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lets take the the price of one orange, one banana and one apple as 'x', 'y', 'z' respectively. now according to the statements we can deduce the equation 1 as, 2x+3y+4z=15.
equation 2 can be shown by, 3x+2y+z=10.
now adding equation 1 and equation,
we get,
5x+5y+5z=25
dividing the whole by 5,
x+y+z=5.
now the cost for 3oranges, 3 bananas, 3apples would be, 3x+3y+3z.
to get that, we multiple the equation 'x+y+z=5' by 3
we thus get, 3x+3y+3z=15
the cost of 3oranges, 3 bananas, 3apples is rs 15.
equation 2 can be shown by, 3x+2y+z=10.
now adding equation 1 and equation,
we get,
5x+5y+5z=25
dividing the whole by 5,
x+y+z=5.
now the cost for 3oranges, 3 bananas, 3apples would be, 3x+3y+3z.
to get that, we multiple the equation 'x+y+z=5' by 3
we thus get, 3x+3y+3z=15
the cost of 3oranges, 3 bananas, 3apples is rs 15.
AshuAbhishek11:
you are right
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