Question

the principal solution of 3cosecA=4sin A is​

Answer 1

Step-by-step explanation:

3/sinsA=4sinA

3/4=sin^2 A

sinA=root of 3/4

Answer 2

Answer:

sinA=√3/2 where A is 60,120.

Step-by-step explanation:

given 3cosecA=4sinA

by transposing cosec A to rhs sit becomes sinA so

3=4sinA.sinA transpose 4 to lhs

3/4=sin^2A

apply square root on both sides

√(3/4)=sinA

sinA=√3/2

therefore A is 60,120.

I hope you are satisfied by my answer.