Question

The principal that will fetch Rs.1280 as interest at 12% p.a for 8 months is

______.​

Answer 1

☯GIVEN :

• Simple Interest (SI) = Rs 1280

• Rate (R) = 12%

• Time (T) = 8 months = $\bf{ \dfrac{2}{3} }$ year.

☯TO FIND :

• Principal (P).

☯FORMULA REQUIRED :

• $\bigstar{\underline { \boxed{ \red{ \bf{P = \dfrac{SI\times 100}{R \times T} }}}}}$

➲SOLUTION :

Substituting the given values :

$\implies {\sf{ P= \dfrac{SI \times 100}{R \times T}}}$

$\implies {\sf{P = \dfrac{1280 \times 100} { \cancel{12} \times \dfrac{2}{ \cancel{3}} }}}$

$\implies {\sf{ P= \dfrac{1280 \times 100} { 4 \times 2 }}}$

$\implies {\sf{P = \dfrac{ \cancel{1280 }\times 100} { \cancel{8}}}}$

$\implies {\sf{P = 160 \times 100}}$

$\implies \underline{ \red{ \boxed{\bf{ P=Rs\:16000}}}}$

$\huge{\pink{\therefore}}$ Principal = Rs 16000.

Answer 2

The answer is rupees 16000