Question

using quadaratic formula find roots of following quadaratic equation

$6 {a}^{2}{x}^{2} - 7abx - 3 {b}^{2} = 0$
where a is not equal to 0​

Answer 1

Step-by-step explanation:

Given 6a2x2 - 7abx - 3b2 = 0 Compare to ax2 + bx + c = 0 a = 6a2 , b = -7ab , c = - 3b2 The quadratic formula to find the roots of quadratic equation are

−

b

±

√

b

2

−

4

a

c

2

a

, where b2 - 4ac is called the discriminant of the quadratic equation. x = [ 7ab ± √(49a2b2 + 72a2b2 )] / 12a2 . x = [ 7ab ± √(121a2b2 ) ] / 12a2 . x = [ 7ab ± 11ab] / 12a2 . x = 18ab / 12a2 or - 4ab / 12a2 . x = 3b / 2a or -b / 3a

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