The probabilities of having lunch in campus canteen for Jimmy, Kitty and Mona in a particular day are 0.8, 0.5 and 0.6 respectively. (Correct your answers to 3 decimal places.) In a particular day, (i) find the probability that all of them are having lunch in campus canteen. (2 marks) (ii) find the probability that none of them are having lunch in campus canteen. (3 marks) (iii) find the probability that at least one of them is having lunch in campus canteen. (2 marks) (iv) find the probability that exactly two of them are having lunch in campus canteen. (4 marks)
Answers
Given : Different probabilities of having lunch in campus canteen for Jimmy, Kitty and Mona in a particular day
To find : probability that all of them are having lunch in campus canteen.
probability that none of them are having lunch in campus canteen
probability that at least one of them is having lunch in campus canteen
ind the probability that exactly two of them are having lunch in campus canteen.
Step-by-step explanation:
Probability of having lunch in canteen by Jimmy = 0.8
Probability of not having lunch in canteen by Jimmy = 1 - 0.8 = 0.2
Probability of having lunch in canteen by Kitty = 0.5
Probability of not having lunch in canteen by Kitty = 1 - 0.5 = 0.5
Probability of having lunch in canteen by Mona = 0.6
Probability of not having lunch in canteen by Mona = 1 - 0.6 = 0.4
probability that all of them are having lunch in campus canteen.
= (0.8)(0.5)(0.4)
= 0.16
probability that none of them are having lunch in campus canteen
= (0.2)(0.5)(0.4)
= 0.04
probability that at least one of them is having lunch in campus canteen.
= 1 - none Having lunch
= 1 - 0.04
= 0.96
exactly two of them are having lunch in campus canteen
= (0.8)(0.5)(0.6) + (0.8)(0.5)(0.4) + (0.2)(0.5)(0.4)
= 0.24 + 0.16 + 0.04
= 0.44
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