Question

The probability for a randomly chosen month to have its 10th day as sunday is

Answer 1

Option (a) $\frac {1}{84}$ is the correct answer.

Step-by-step explanation:

• The Probability of choosing a month from a Year = $\frac {1}{12}$

• Since there are Seven Days in a Week, So, The Probability of choosing a day from a Week (Sunday) = $\frac {1}{7}$

Now,

• Probability for a randomly chosen month to have its Tenth (10th) Day as Sunday = $\frac {1}{12} \times \frac {1}{7}$

= $\frac {1}{84}$

Answer is Option (a)

Answer 2

Given: Randomly chosen month to have its $10^{th}$ day as Sunday.

To Find: The probability for a Randomly chosen month to have its $10^{th}$ day as Sunday.

Step-by-step explanation:

Probability of any chosen month out of $12$ months$=\frac{1}{12}$

There are seven possible ways in which a month can start and it will be a Sunday on the $10^{th}$ day.

So, Its probability$=\frac{1}{7}$

Thus, required probability $=\frac{1}{7}\times \frac{1}{12}$

                                            $=\frac{1}{84}$

Therefore, The probability for a randomly chosen month to have its $10^{th}$day as Sunday is $\frac{1}{84}$.