The probability of a leap year selected at random contain 53 Sunday is:
(a) 53/ 366
(b) 1/7
(c) 2/7
(d) 53/365
Answers
Answered by
5
Answer:
Option C, 2/7
Brief explanation:-
In a leap year there are 366 days .
We have,
366 days = 52 weeks and 2 days
Thus, a leap year has always 52 Sundays.
The remaining 2 days can be:
(i) Sunday and Monday
(ii) Monday and Tuesday
(iii) Tuesday and Wednesday
(iv) Wednesday and Thursday
(v) Thursday and Friday
(vi) Friday and Saturday
(vii) Saturday and Sunday.
Clearly, there are seven elemetary events associated with this random experiment.
Clearly, the event will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.
∴ Favourable number of elementary events = 2
Hence, required probability = 2/7.
Answered by
26
2/7 is the answer.......
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