the probability of a student A passing an examination is 3/7 and of student B is 5/7 assuming the two event A passes, B passes as independent,find the probability only one of them passing the examination
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the probability of A passing the exam is 3/5 = .6
the probability of A failing the exam is 2/5 = .4
the probability of B passing the exam is 4/5 = .8
the probability of B failing the exam is 1/5 = .2
the probability of both students passing the exam is .6 * .8 = .48
the probability of only A passing the exam is .6 * .2 = .12
the probability of only one of them passing the exam is .6 * .2 + .4 * .8 = .12 + .32 = .44
the probability of neither passing the exam is .4 * .2 = .08
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