The probability of getting 7 in throwing a die once is ……….
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2
Answer:
No. of possible outcome = (1,2,3,4,5,6 )
= 6
probability of getting 7 = Favourable outcome / total no. of outcome
= 0/6
= 0
Step-by-step explanation:
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10
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ANSWER= SINCE THERE IS NO 7 NO.IN THE DIE ..THE PROBABLITY OF GETTING 7 =0
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