Question

The probability of getting a factor of 6 in the experiment of throwing a dice is

Answer 1

The probability of getting a factor of 6 in the experiment of throwing a dice is 2 / 3.

• A factor of 6 is a number which leaves no remainder on dividing 6 by that number.

• A dice has the numbers 1, 2, 3, 4, 5, and 6 on its six respective faces.

• Let us check each number for the factor of 6.

6 / 1 = Quotient = 6, Remainder= 0

6 / 2 = Quotient = 3, Remainder = 0

6 / 3 = Quotient = 2, Remainder = 0

6 / 4 = Quotient = 1, Remainder = 2

6 / 5 = Quotient = 1, Remainder = 1

6 / 6 = Quotient = 1, Remainder = 0

Therefore, the factors of 6 among these numbers are : 1, 2, 3, and 6.

• Probability of an event = Total number of favourable outcomes / Total number of possible outcomes

• Here,

Event = Getting a factor of 6

Favourable outcomes = 1, 2, 3, and 6

⇒Total number of favourable outcomes = 4

Possible outcomes = 1, 2, 3, 4, 5, and 6

⇒Total number of possible outcomes = 6

• Therefore,

Probability of getting a factor of 6 = Total number of factors of 6 / Total number of possible outcomes

=> Probability of getting a factor of 6 = 4 / 6 = 2 / 3