Question

The probability of getting a total score of 7 .when two unbiased dice are thrown simultaneously

Answer 1

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Answer 2

Answer:

$\frac{1}{6}$

Step-by-step explanation:

Total outcomes = 36

{1,1};{1,2};{1,3}{1,4};{1,5};{1,6}

{2,1};{2,2};{2,3}{2,4};{2,5};{2,6}

{3,1};{3,2};{3,3}{3,4};{3,5};{3,6}

{4,1};{4,2};{4,3}{4,4};{4,5};{4,6}

{5,1};{5,2};{5,3}{5,4};{5,5};{5,6}

{6,1};{6,2};{6,3}{6,4};{6,5};{6,6}

Favorable outcomes = Sum of 7 = {1,6};{2,5};{3,4};{4,3};{5,2};{6,1} =6

Probability of getting a sum of 7 = $\frac{\text{favorable outcomes}}{\text{Total outcomes}}$

                                                     = $\frac{6}{36}$

                                                     = $\frac{1}{6}$

Hence the probability of getting a total score of 7 is  $\frac{1}{6}$.