Question

The probability of getting exactly 2 tails in 6 tosses of a fair coin is

Answer 1

Answer:

Using Baye's theorem:

P = (1/2)^2 * (1/2)^4 * 6! / (2! * 4!) = (1/2)^6 * 6! / (2! * 4!)

P = 1/64 * 720 / (2 * 24) = .234

This basically is the probability of 2 wins * 4 failures

multiplied by the total permutations of these events

divided by the number of combinations of 6 things taken 2 at a time