Question

The probability of getting exactly one head in tossing a pair of coins is
a. 0
b. 1
c. 1/3
d. 1/2

Answer 1

Answer:

The possible outcomes when two coins are tossed together are {HH,TT,HT,TH}. Therefore, the number of possible outcomes when two coins are tossed is 4.

Now, the possible outcomes of getting exactly one head are {HT,TH}, which means the number of favourable outcome is 2.

 

Therefore, probability P of getting exactly one head is:

 

P= 4/2

​  

= 1/2

​  

   

 

Hence, the probability of getting exactly one head is  

1/2

​  

.

Step-by-step explanation:

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Answer 2

Given:

Pair of coins are tossed.

To Find:

The probability of getting exactly one head.

Solution:

The probability of an event can be defined as the ratio of the number of favorable outcomes to the total number of possible outcomes

$P(E)=\frac{No. of favorable outcomes}{No. of possible outcomes.}$

When two coins are tossed, the possibilities are getting two heads, getting two tails, getting a head on one and a tail on the other.

So the sample space will be {HH, HT, TH, TT}

Here, the number of favorable outcomes is equal to 2 and the total number of possible outcomes is equal to 4.

Required probability $P(E)=\frac{2}{4}=\frac{1}{2}$

Hence, the probability of getting exactly one head is $\frac{1}{2}$.

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