Question

The probability of getting only heads when you toss two coins together

Answer 1

✨ Here is your answer

Let E1 = event of getting 2 heads. Then,

E1 = {HH} and, therefore, n(E1) = 1.

Therefore, P(getting 2 heads) = P(E1) = n(E1)/n(S) = 1/4.

Mark it BRAINLIEST ✨

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Answer 2

when two coins are tossed simultaneously

Total no of outcome =4(HH,HT,TH,TT)

chances of getting one head =2(HT,TH)

probability=2/4=1/2

hope this helps you