Math, asked by vanshikaraghuvanshi, 4 months ago

The probability of getting two heads when two coins are tossed is..

a. 1/2

b. 1/4

c. 1

d. 3/4

sub offline hogaye !!.. :(​

Answers

Answered by joshianuvrat
2

Answer:

sample space = {HH, HT, TH, TT}

Step-by-step explanation:

probability of getting two heads = 1/4

Answered by leotash
1

Answer:

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Step-by-step explanation:

The sample space for two unbiased coins tossed together is

{HH, HT, TH, TT}.

From the four possible outcomes, HH is the favorable one. So

P(both coins show heads on one toss) = number of favorable outcomes ÷ number of outcomes in the sample space = 1/4

Alternatively, if these coins are balanced, then the probability of getting heads on a toss of either one of them is P(head) = 1/2. One toss is independent of the other, so

P(both coins show heads) = P(1st coin shows a head) × P(2nd coin shows a head) = 1/2×1/2 = 14.

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