Question

The probability of having a surprise test is 1/5.If a student is absent twice , what is the probability that he will miss atleast one test?​

Answer 1

Answer:

Step-by-step explanation:

This is how I've solved this question hope it helps.

That is: P(Event A occurs) = 1- P(Event A does not occur)

So, P(miss at least 1 test) =1 - P(miss no tests)

P(miss no tests)

P(miss no tests) = P(no test on day 1 AND no test on day 2)

= P(no test on day 1) × P(no test on day 2)

=4/5 X 4/5

=16/25

So, P(miss at least 1 test) = 1 - P(miss no tests)

=1−16/25

=9/25