Question

The probability of hitting a target is 1/5. Two bombs are enough to destroy a bridge. If six bombs are aimed at a bridge, find the probability that the bridge is destroyed

Answer 1

Answer:

Step-by-step explanation:

The probability to hit the target is 1/5.

If six bombs are there theme it is 6/5.

The bombs hit Will be 1.2

So, probability of destroying the bridge= 60%

Answer 2

Answer:

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Step-by-step explanation:

The bridge will only survive if no bombs hit the bridge or if only 1 of the six does.

The probability no bombs hit is  (4/5)6 .

The probability that the first one hits and The others miss is  (1/5)∗(4/5)5  but the same applies to the second, third, … sixth, so the chance exactly one hits is  (6/5)∗(4/5)5 .

Finally, the chance that the bridge is destroyed is 1 minus the probability of zero or only one hit, which is

1−(6/5)∗(4/5)5−(4/5)6  which we can rearrange to give  1−(4/5)5∗(6/5+4/5)  =  1−2∗(4/5)5  =  −0.65536=0.34464 .