The probability of making an even number of 4digits using 1,2,3 and 4 with out any digit being repeated
Answers
Answered by
17
By Fundamental Principle of Counting,
Total Number of possibilities = 4!
= 24.
Favourable Outcomes = 2 X 3! = 12
PROBABILITY = FAVOURABLE OUTCOMES/TOTAL OUTCOMES.
→ probability = 12/24 = 1/2.
:)
Total Number of possibilities = 4!
= 24.
Favourable Outcomes = 2 X 3! = 12
PROBABILITY = FAVOURABLE OUTCOMES/TOTAL OUTCOMES.
→ probability = 12/24 = 1/2.
:)
Answered by
1
Given:
Total digits = 4
The digits = 1, 2, 3 and 4
To Find:
The probability of making an even number of 4digits using 1,2,3 and 4 without being repeated
Solution:
The number of ways that the four digits formed by the digits 1, 2, 3 4 without repetition will be = 4!
= 4 × 3 × 2 × 1
= 24
Now, the favourable outcomes will be
= 2 × 3!
= 2 × 3 × 2 × 1
= 12
Probability of making an even number = Favourable Outcomes/ Total Outcomes
= 12/24
= 1/2
Answer: The probability of making an even number of 4digits using 1,2,3 and 4 without being repeated is 1/2.
Similar questions