Math, asked by doctorsunidhi2334, 1 year ago

The probability of making an even number of 4digits using 1,2,3 and 4 with out any digit being repeated

Answers

Answered by FahadNazmi
17
By Fundamental Principle of Counting,
Total Number of possibilities = 4!
= 24.
Favourable Outcomes = 2 X 3! = 12
PROBABILITY = FAVOURABLE OUTCOMES/TOTAL OUTCOMES.
→ probability = 12/24 = 1/2.

:)
Answered by Anonymous
1

Given:

Total digits = 4

The digits = 1, 2, 3 and 4

To Find:

The probability of making an even number of 4digits using 1,2,3 and 4 without being repeated

Solution:

The number of ways that the four digits formed by the digits 1, 2, 3 4 without repetition will be = 4!

= 4 × 3 × 2 × 1

= 24

Now, the favourable outcomes will be

= 2 × 3!

= 2 × 3 × 2  × 1

= 12

Probability of making an even number = Favourable Outcomes/ Total Outcomes

= 12/24

= 1/2

Answer: The probability of making an even number of 4digits using 1,2,3 and 4 without being repeated is 1/2.

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