Question

The probability of throwing a number greater than 2 with a fair dice is
(a)$\frac{3}{5}$
(b)$\frac{2}{5}$
(c)$\frac{2}{3}$
(d)$\frac{1}{3}$

Answer 1

SOLUTION :  

The correct option is (c) : ⅔ .

Given : A die is thrown once .

A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.

If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6

Number of possible outcomes are = 6

Let E = Event of getting a number greater than 3  

Number greater than 3 are = 3,4,5, 6

Number of outcome favourable to E = 4

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 4/6  = 2/3

Hence, the probability of getting a  number greater than 3 , P(E) = 2/3

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Answer 2

The answer is 2/3...

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