Question

the probability of throwing an odd number twice with an ordinary six faced die consecutively is

Answer 1

The probability will be 7/21 = 1/3


Hope this helps!

Answer 2

Answer:

The Probability of throwing an odd no. twice is $\frac{1}{13}$

Step-by-step explanation:

Given: A die is tossed 2 times consecutively,

To find: Probabilty of getting an odd no on both dice

Total no of outcome = 6² = 36

Favorable outcome = ( 1 , 1 ) , ( 3 , 3 ) , ( 5 , 5 )

No of Favorable outcome = 3

$Probabilty=\frac{No.\:of\:Favorable\;outcome}{Total\;No.\;of\:Outcome}$

$Probabilty=\frac{3}{36}$

$Probabilty=\frac{1}{12}$

Therefore, The Probability of throwing an odd no. twice is $\frac{1}{13}$