Question

The probability that a bullet fired from a point will strike the target is 3/4. 5 such bullets are fired simultaneously toward the target from that very point. What is the probability that the target will be strike?

Answer 1

Answer:

The probability of the target strike = $\frac{1023}{1024}$

Step-by-step explanation:

Probability of striking a target = $\frac{3}{4}$

No. of trails = 5

Let success = striking a target = $\frac{3}{4}$ (Let it be 'p')

Failure = not striking a target = $\frac{1}{4}$ (Let it be 'q')

We need to find the probability of striking the target

P(Striking) = 1 - P(not striking)

                 = 1 -  $\frac{1}{4}$ * $\frac{1}{4}$ * $\frac{1}{4}$ * $\frac{1}{4}$ * $\frac{1}{4}$

                 = 1 - $(\frac{1}{4})^5$

                 = 1 - $\frac{1}{1024}$

                 = $\frac{1023}{1024}$

The probability of the target strike = $\frac{1023}{1024}$

Answer 2

Step-by-step explanation:

Given:

a bullet fired from a point will strike the target is 3/4

Solution:

Probability of missing is

$1-\frac{3}{4} = \frac{1}{4}$

When 5 shots are fired, the probability of missing is

$(\frac{1}{4} )^5$

Hence probability of hit is

$1 - (\frac{1}{4} )^5$

=0.99902

#SPJ2