Question

The probability that a student will pass math is 3/5, and the probability that he'll pass english is 1/3. If the probability that he'll pass both math and english is 1/8, what is the probability that he'll pass at least one subject?

Answer 1

Answer:

7/8

Step-by-step explanation:

8/8=1

8/8-1/8=

7/8

Answer 2

The probability that he'll pass at least one subject is 0.808.

Step-by-step explanation:

Given : The probability that a student will pass math is 3/5, and the probability that he'll pass English is 1/3. If the probability that he'll pass both math and English is 1/8.

To find : What is the probability that he'll pass at least one subject?

Solution :

Let A be the event that a student will pass math.

The probability that a student will pass math is

$P(A)=\frac{3}{5}$

Let B be the event that a student will pass English.

The probability that a student will pass English is

$P(B)=\frac{1}{3}$

P(A and B) = probability that he'll pass both math and English

So, $P(A\cap B)=\frac{1}{8}$

The probability of passing in at least one subject is actually the  P(Math or  English) i.e. P(A or B)

$P(A\cup B) = P(A) + P(B) - P(A\cap B)$

Substitute the values,

$P(AUB) =\frac{3}{5}+ \frac{1}{3}-\frac{1}{8}$

$P(AUB) =\frac{72+40-15}{120}$

$P(AUB) =\frac{97}{120}$

$P(AUB) =0.808$

Therefore, the probability that he'll pass at least one subject is 0.808.

#Learn more

A student has 60% chance of passing in English and 54% chance of passing in both English and maths. What is the percentage probability that he will fail in maths ?

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