Math, asked by Bagali7, 1 year ago

The probability that Henk goes swimming on any day is 0.2. On a day when he goes swimming, the probability that Henk has burgers for supper is 0.75. On a day when he does not go swimming the probability that he has burgers for supper is x. This information is shown on the following tree diagram.
The probability that Henk has burgers for supper on any day is 0.5. (i) Find x.
(ii) Given that Henk has burgers for supper, find the probability that he went swimming that day.

Answers

Answered by kokan6515
7
Ist part ans is 0.73
and Iind part ans is 0.27
Hope this helps
Attachments:

akhilasai: could u explain more clearly ?
kokan6515: it is based on bayes theorem
akhilasai: ? out of my portion
kokan6515: u r in which class??
Answered by prateekmishra16sl
0

Answer: Value of x is 0.4375

Probability that Henk went swimming , given that he had burgers is 0.3

Step-by-step explanation:

Ways of Henk to eat burger :

  1. He goes swimming and eats burger for supper
  2. He does not goes to swimming and eats burger for supper

Probability of Henk having burger = Probability of Henk going to swimming and having burger + Probability of Henk not going to swimming and having burger

Net probability = (0.2 × 0.75) + (0.8 × x)

0.5 = 0.15 + 0.8x

0.8x = 0.35

x = 0.4375

P(A) ⇒ Probability of Henk having burger

P(B) ⇒ Probability of Henk going to swimming

Probability that he went swimming , given that he has burgers ⇒ P(B∩A)/P(A) = (0.2 × 0.75) /0.5 = 0.3

#SPJ3

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