The Probability that there is at least one error in an account statement prepared by A is 0.3 for B is 0.4 and for C it is 0.45.If A,B and C prepared 20,10 and 40 statements respectively .What is the expected number of correct statements.
Answers
Answer:
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The expected number of correct statements is 42
Given:
The Probability that there is at least one error in an account statement prepared by A is 0.3 for B is 0.4 and for C it is 0.45
A,B and C prepared 20,10 and 40 statements respectively
To Find:
the expected number of correct statements.
Solution:
At least one error in an account statement prepared by A is 0.3
No Error by A = 1 - 0.3 = 0.7
Expected correct Statement by A = 20 ( 0.7) = 14
At least one error in an account statement prepared by B is 0.4
No Error by B = 1 - 0.4 = 0.6
Expected correct Statement by B = 10 ( 0.6) = 6
At least one error in an account statement prepared by C is 0.45
No Error by C = 1 - 0.45 = 0.55
Expected correct Statement by C = 40 ( 0.55) =22
Expected Number of correct Statements = 14 + 6 + 22 = 42
The expected number of correct statements is 42