the probability that two different friend have different birthdays (ignoring a leap year) is :
a) 364/365
b) 1/365
c) 1/73
d) 3/73
plz explain in short also...
Answers
Answered by
72
total number of days n(s)= 365
we know that two different friend birthday was same on 1 day in a year
so 365-1= 364 days are different for each friend
so, n(E)=364
therefore p(E)= n(E)/n(S)
= 364/365
option 1 is correct
we know that two different friend birthday was same on 1 day in a year
so 365-1= 364 days are different for each friend
so, n(E)=364
therefore p(E)= n(E)/n(S)
= 364/365
option 1 is correct
Answered by
14
Option a) 364/365 is correct.
Similar questions