Physics, asked by shivanikardam9843, 8 months ago

The process on an ideal gas, shown in figure, is
(a) isothermal
(b) isobaric
(c) isochoric
(d) none of these.
Figure

Answers

Answered by Anonymous
8

Answer:

(c) isobaric....

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Answered by bhuvna789456
1

The process on an ideal gas, shown in attached figure, is isochoric

Explanation:

Step 1:

As we know that

P is directly proportional to T, in accordance with the graph

Applying State Equation

We get  

PV = nRT

P=\frac{n R}{v} T  

where

n =  physical law which describes the relation between the measurable properties of an ideal gas  

P is pressure

V is volume  

n is  number of moles

R is the gas constant

T is  temperature in Kelvin

Step 2:

Given : P directly proportional to T  

Which means \frac{n R}{v} is a constant , But V still remains constant

Constant v means isochoric cycle  

Therefore the correct answer is Option (c) isochoric

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