Question

the prodeut of four consecutive positive integers is 840 find the number.

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Answer 1

Step-by-step explanation:

Let the four consecutive integers be, n,n+1,n+2,n+3

then, n(n+1)(n+2)(n+3)=840

n(n+1)(n+2)(n+3)=4×5×6×7

Comparing, we get n=4

Thus, the numbers are 4,5,6,7.

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