Question

The product formed in the reaction of SOCl2 with white phosphorous is (a) PCl3 (b) SO2Cl2 (c) SCl2 (d) POCl3

Answer 1

When $SOCl_2$ reacts with white phosphorous, it yields $PCl_3$ as product.

Explanation:

• The chemical called Phosphorus trichloride is prepared treating white phosphorous with chlorine and thionyl chloride.
• The reaction given involves the interaction of white phosphorous with thionyl chloride.
• The equation for the reaction is as follows:

$P_4+8SOCl_2\rightarrow 4PCl_3 + 4SO_2+ 2S_2Cl_2$

• From the above equation it is clear that when white phosphorous reacts with thionyl chloride it leads to three products namely:

1. Phosphorus trichloride$(PCl_3)$
2. Sulfur dioxide $(SO_2)$
3. Di sulfur dichloride$(S_2Cl_2)$

• Thus among the options given in the question, option 'a' is correct.

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