The product of -12 and positive integer 7 find the integer.
Answers
Answer:
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Step-by-step explanation:
In ||gm ABCD, E is the mid-point of AB and F is the mid-point of DC. Also AB|| DC.
AB = DC and AB || DC
∴ (1/2)AB = (1/2)DC and AE || DF (Since E and F mid point of AB and DC)
∴ AE = (1/2)AB and DF = (1/2)DC
∴ AE = DF and AE || DF
∴Quadrilateral AEFD is a parallelogram Similarly, Quadrilateral EBCF is a parallelogram.
Now parallelogram AEFD and EBCF are on equal bases DF = FC and between two parallels AB and DC
∴ ar(||gm AEFD) = ar(||gm EBCF)
when we multiply
2*2=4
2*1=2
2*0=0
as we can see in the above example as one factor decreases the product decreases by 2.
so now if we multiply 2*(-1) we get 0 - 2 = -2
so 2*(-1)=-2
2*(-2)=(-4)
and so on...............
Step-by-step explanation:
the site of the product will be negative