Question

the product of 2 consecutive integers is 56.find the two integers

Answer 1

Answer: Factors if 56 are,
56=1, 2, 4, 7, 8, 14, 28, 56

Hence two consecutive integers are 7 and 8.
7*8 = 56

Hope this is helpful.

Answer 2

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

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• The product of 2 consecutive integers is 56 .

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

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• Two consecutive numbers = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

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Let 2 consecutive integers be x and x + 1

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Acc. to the question :-

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x ( x + 1 ) = 56

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x² + x = 56

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x² + x - 56 = 0

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x² - 7x + 8x - 56 = 0

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x ( x - 7 ) + 8 ( x - 7 ) = 0

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( x + 8 ) ( x - 7 ) = 0

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☆ x + 8 = 0

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x = - 8

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If x = - 8

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Then another no. = x + 1 = -8 + 1 = -7

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☆ x - 7 = 0

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x = 7

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If x = 7

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Then another no. = x + 1 = 7 + 1 = 8

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

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• 2 consecutive no. = 7 and 8 OR -8 and -7