Question

the product of 3 consecutive numbers is 3360 what is the least number

Answer 1

Answer:

14

Step-by-step explanation:

factors of 3360 are

3360=2 x 2 x 2 x 2 x 2 x 3 x 5 x 7

= (2 x 7) x (3 x 5)   x (2 x 2 x 2 x 2)

3360=14  x 15 x 16

So the numbers are 14,15 and 16

the smallest no.=14

Answer 2

The least number is 14.

Step-by-step explanation:

Given : The product of 3 consecutive numbers is 3360.

To find : What is the least number ?

Solution :

Let the numbers be (x-1), x and (x+1).

The product of 3 consecutive numbers is 3360.

i.e. $(x-1)(x)(x+1)=3360$

$(x)(x^2-1)=3360$

$x^3-x-3360=0$

One of the factor of the equation is 15.

#Check

$15^3-15-3360 = 0$

So, the value of x=15.

$x-1=15-1=14$

$x+1=15+1=16$

The numbers are 14,15 and 16.

Therefore, the least number is 14.

#Learn more

The sum of 5 consecutive numbers is 900. Find them

https://brainly.in/question/10496457