the product of 4 consecutive positive integers is 840 . find the numbers.
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4
x+x+1+x+2+x+3=840
4x+6=840
x=834/4
x=217
then as well as 218,219,220
4x+6=840
x=834/4
x=217
then as well as 218,219,220
kratikavarshney62:
please mark as brainlist
Answered by
6
let first = x
second = x +1
third = x +2
fourth = x + 3
product =
x × x +1 × x + 2 × x + 3 = 840
x^2 + x + 2x + 3 = 840
x^2 + 3x = 837
x^2 = 279
x= under root 279
second = x +1
third = x +2
fourth = x + 3
product =
x × x +1 × x + 2 × x + 3 = 840
x^2 + x + 2x + 3 = 840
x^2 + 3x = 837
x^2 = 279
x= under root 279
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