The product of electrolysis of dilute NaCl should be, O2, H2 and NaOH but it is Cl2,
H2 and NaOH. explain.
Answers
Answered by
2
Answer:
Correct option is
A
49
2NaCl⇌2Na
+
+2Cl
−
2H
2
O⇌2H
+
+2OH
−
At anode:
2Cl
−
→Cl
2
+2e
−
At cathode :
2H
+
+2e
−
→H
2
Net reaction (8 5 5:)
2NaCl+2H
2
O⇌2OH
−
+H
2
+Cl
2
+2Na
+
1000=
96500
35.5
×25.62×t
t=175374.83sec=48.74hr.
moles of OH
−
=
71
1000
×2
volume =20L
[OH
−
]=
71×20
2000
=1.408M
Answered by
1
Explanation:
Since dilute NaCl contains water molecules also
Therefore it will become brine water (NaCl + H₂O)
and the product of electrical decomposition or electrolysis of brine water
Gives us
NaOH (sodium hydro oxide aka caustic soda)
Cl₂ - at the anode
H₂ + at the cathode
This process is also known as the chloralkali process you can find more about it on the internet or in the textbook of 10th
here's a pic of this process
Attachments:
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