The product of first three terms of G.P is 1000. If 6 is added to its second term and
7 is added to its third term, the terms become in A.P. Find G.P
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Answer:
The product of first three terms of G.P is 1000. If 6 is added to its second term and
7 is added to its third term, the terms become in A.P. Find G.P
PLEASE WRITE STEP BY STEP
GiveN:
The product of first three terms of a G.P is 1000.
1000.If 6 is added to its second term and 7 added to its third term, the terms form in AP.
To FinD:
- The GP?
Step-by-step Explanation:
We have the three terms in GP.
Let the terms be a/r, a, ar
According to question,
⇒ a/r × a × ar = 1000
⇒ a³ = 1000
⇒ a³ = 10³
⇒ a = 10
Now it is given that when 6 is added to its second term and 7 added to its third term, the terms form in AP.
- The second term will be a + 6
- And third term will be ar + 7
- And we know that when the terms form in AP,
2(Second term) = First term + Third term
Plugging the given values:
⇒ 2(a + 6) = a/r + ar + 7
⇒ 2(10 + 6) = 10/r + 10r + 7
⇒ 32 = 10/r + 10r + 7
⇒ 10/r + 10r = 25
⇒ 10 + 10r² / r = 25
⇒ 10r² + 10 = 25r
⇒ 2r² - 5r + 2 = 0
Finding values of r by middle term factorisation,
⇒ 2r² - 4r - r + 2 = 0
⇒ 2r(r - 2) - 1(r - 2) = 0
⇒ (2r - 1)(r - 2) = 0
⇒ Then, r = 1/2 , 2
Hence,