the product of four consecutive natural numbers is 1850. find the natural number
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Let the no.s be
1st no. = x
2nd no. = x+1
3rd no. = x+2
4th no. = x+3
x + (x+1) + (x+2) + (x+3) + = 1850
x + x + 1 + x + 2 + x + 3= 1850
4x + 6 = 1850
4x = 1850 - 6
4x = 1844
x = 1844/4
x = 461
Therefore
1st no. = x
= 461
2nd no. = x+1
= 461 + 1
= 462
3rd no. = x+2
= 461 + 2
= 463
4th no. = x+3
= 461 + 3
= 464
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