Question

(x-2y)^3 - 2(x-2y)^2

Answer 1

Answer:

(x^3-8y^3) - 2(x^2-4y^2)

x^3-8y^3 - 2x^2-8y^2

wait...x^3-2x^2 = x^3 - x^3 = 0

and -8y^3 - 8y^2 = - 16y^5

all wrong (i think)