Question

the product of four consecutive positive integer is 840 find the numbers​

Answer 1

Explanation:

Let the 4 consecutive number be x,x+1,x+2,x+3..

(x)(x+1)(x+2)(x+3)=840

x×x+1×x+2×x+3=840

x(4)×(1×2×3)=840

x(4)×6=840

x(4)=840/6

x(4)=140×1/4

x=140/4

x=35

• First positive consecutive integer is x

x=35

• Second positive consecutive integer is x+1

x+1=35+1

36

• Third positive consecutive integer is x+2

x+2=35+2

37

• Fourth positive consecutive integer is x+3

x+3=35+3

38