the product of slopes of lines 3y=-2x+3 and 5x-5y=1 is
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Given : lines 3y=-2x+3 and 5x-5y=1 is
To find : product of slopes of lines
Solution:
y = mx + c is a line where slope = m
3y=-2x+3
Diving both sides by 3
=> y = (-2/3)x + 1
hence m = -2/3
Slope = -2/3
5x-5y=1
=> 5y = 5x - 1
Diving both sides by 5
=> y = x - 1/5
hence m = 1
Slope = 1
Product of slopes of lines = (-2/3)(1) = -2/3
product of slopes of lines 3y=-2x+3 and 5x-5y=1 is -2/3
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