Math, asked by HARSH2001, 1 year ago

the product of sunita age two years ago and her age four years from now is one more than twice her present age. what is her present age

HARSH2001: and can u tell me I should refer any books or questions paper for psa

lifeislife: u could refer the CCE book

lifeislife: mostly u can also the Oswaal book of series

HARSH2001: ok thanxx Bro

lifeislife: fine, :)

Answers

Answered by lifeislife

Let her present age be x.
Two years ago:- x-2.
four years from now:- x+4.
one more than twice her present age:- 1+2x.
(x-2)(x+4)=1+2x.
x²+4x-2x-8=1+2x.
x²+2x-2x-8-1=0.
x²-9=0.
x²=9.
Therefore, x= plus or minus 3.
Age cannot be negative.
Therefore, x=3.
Therefore, her present age is 3 years.

Thank you.
Hope this will help you.

lifeislife: thank you

lifeislife: Pls mark it as the best.

HARSH2001: thank you

lifeislife: no mention

lifeislife: :)

HARSH2001: can u suggest me which book I should refer for cbse 10

lifeislife: you could prepare for exams by using the R.D. Sharma guide

lifeislife: it will have man questions, and practice it when ou were free, thank you

Answered by priyav

Sunitha ' s present age = x sunitha ' s age before 2 years= x-2 Sunitha ' s age after 4 years = x+4 product = (x-2)(x+4) = x^2 + (4-2 ) x -8 Product = 1 +2x (given) = x^2 + (4-2 ) x -8 = 1 +2x x^2 + 2x-8=1+2x x^2= 1 +2x-2x+8 =9 X = root9 =3 Therefore sunitha ' s present age is 3years

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