Question

The product of Tanays age (in years) five years ago and his age ten years later is 16. Determine Tanays age.​

Answer 1

Answer:

Let tanay's present age be x yrs

five yrs ago tanay's age = x-5

ten yrs later tanay's age =x+10

according to the question.,

=(x-5)(x+10)=16

=x^2 +10x-5x-50=16

=x^2+5x-66=0

=x^2+11x-6x-66=0

=x (x+11)-6 (x+11)=0

=(x-6)(x+11)=0

=x=6 or x=-11

since age is positive tanay's present age =6yrs

Answer 2

The age of Tanya will be "6".

Step-by-step explanation:

$Let \ the \ present \ age \ of \ Tanya=x\\5 \ years \ ago,her \ age=x-5\\10 \ years \ later,her \ age=x+10\\According \ to \ the \ question,\\(x-5)(x+10)=16\\x(x-5)+10(x-5)=16\\x^2-5x+10x-50-16=0\\x^2+5x-66=0\\x^2+11x-6x-66=0\\x(x+11)-6(x+11)=0\\(x-6)(x+11)=0\\x-6=0\\x=6\\x+11=0\\x=-11$

Since, the age will be in positive i.e, "6".

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