Question

The product of the following is
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Answer 1

Step-by-step explanation:

2ab(6a

2ab(6a 2

2ab(6a 2 −7b+5ab)=2ab×6a

2ab(6a 2 −7b+5ab)=2ab×6a 2

2ab(6a 2 −7b+5ab)=2ab×6a 2 −2ab×7b+2ab×5ab

2ab(6a 2 −7b+5ab)=2ab×6a 2 −2ab×7b+2ab×5ab =12a

2ab(6a 2 −7b+5ab)=2ab×6a 2 −2ab×7b+2ab×5ab =12a 3

2ab(6a 2 −7b+5ab)=2ab×6a 2 −2ab×7b+2ab×5ab =12a 3 b−14ab

2ab(6a 2 −7b+5ab)=2ab×6a 2 −2ab×7b+2ab×5ab =12a 3 b−14ab 2

2ab(6a 2 −7b+5ab)=2ab×6a 2 −2ab×7b+2ab×5ab =12a 3 b−14ab 2 +10a

2ab(6a 2 −7b+5ab)=2ab×6a 2 −2ab×7b+2ab×5ab =12a 3 b−14ab 2 +10a 2

2ab(6a 2 −7b+5ab)=2ab×6a 2 −2ab×7b+2ab×5ab =12a 3 b−14ab 2 +10a 2 b

2ab(6a 2 −7b+5ab)=2ab×6a 2 −2ab×7b+2ab×5ab =12a 3 b−14ab 2 +10a 2 b 2

Answer 2

Answer:

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Step-by-step explanation:

$(6 {a}^{2} - 7b + 5ab) \times 2ab \\ = > 12 {a}^{3} - 14a {b}^{2} + 10 {a}^{2} {b}^{2}$

$= > 12 {a}^{3} - 14a {b}^{2} + 10 {a}^{2} {b}^{2}$

$(6 {a}^{2} - 7b + 5ab) \times 2ab = 12 {a}^{3} - 14a {b}^{2} + 10 {a}^{2} {b}^{2}$