The Product of the LCM and HCF of two numbers is 24. The difference of the two numbers is 2. Find the Numbers ?
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Answered by
26
Answer:
Step-by-step explanation:
Let the no be x and y.
Then, x - y =2
Now, the product of lcm and hcf of two no = product of two no
Accordingly, lcm× hcf = x×y.
=x×y = 24.
From eq 1- x =2+y
Putting the value of x in eq 2,
(y+2)y= 24 = y2(square) + 2y - 24 =0
=y2 + 6y - 4y -24= 0
= y(y+6) - 4(y+6) =0
= (y+6)(y-4)= 0
= y=-6 and y= 4.
harpindersingh529:
thanks
Answered by
1
Answer:
Step-by-step explanation:
Let the no be x and y.
Then, x - y =2
Now, the product of lcm and hcf of two no = product of two no
Accordingly, lcm× hcf = x×y.
=x×y = 24.
From eq 1- x =2+y
Putting the value of x in eq 2,
(y+2)y= 24 = y2(square) + 2y - 24 =0
=y2 + 6y - 4y -24= 0
= y(y+6) - 4(y+6) =0
= (y+6)(y-4)= 0
= y=-6 and y= 4.
Step-by-step explanation:
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