Question

The product of the zeros of the equation 4x²-5x+28=0

Answer 1

Let zeros of given eqn be α and β

we know that,

αβ=c/a and in the given eqn a=4 b=-5 nd c=28[a nd b are the coefficient of x² nd x respectively nd c is constant]

hence product of zeros=αβ=c/a=28/4=7...........Answer

Hope this help!