Question

The product of the zeros of the polynomial 4xsquare+3x+7

Answer 1

$\tt 1)\: 4 {x}^{2} + 3x + 7 \\ \\ \bf a = 4 \: \:\\ \\\bf b = 3 \: \\\\\bf c = 7 \\ \\ \tt product \: of \: zeros = \frac{c}{a} ={\underline{\boxed{\bf\red{\frac{ \: 7 \: }{4}}}}}$

Answer 2

Step-by-step explanation:

$\begin{gathered}\tt 1)\: 4 {x}^{2} + 3x + 7 \\ \\ \bf a = 4 \: \:\\ \\\bf b = 3 \: \\\\\bf c = 7 \\ \\ \tt product \: of \: zeros = \frac{c}{a} ={\underline{\boxed{\bf\red{\frac{ \: 7 \: }{4}}}}}\end{gathered}1)4x2+3x+7a=4b=3c=7productofzeros=ac=47</p><p></p><p>\begin{gathered} \\ \\ \end{gathered}</p><p>$