The product of three consecutive integers is 120. Which is the largest integer?
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Answered by
1
Answer:
( x - 1 ), ( x ), ( x + 1 ). It is given that there product is 120. Hence the sum of the integers is 15.
hope it will help you friend
Answered by
0
Answer:
Consecutive factors are
1,2,3,4,5,6
1×2×3=6
2×3×4=24
3×4×5=60
4×5×6=120
4×5×6120
three consecutive integers are 4 , 5 and 6 , whose product is 120.
and 6 is the greatest number.
Hope it helps you.
Thank you.
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