the product of two 2-digit number is 1998 . If the product of their units digits is 28 and that of tens digits is 15 , find the number .
PLEASE ANSWER IN FULL FROM ...,,,, THIS IS VERY DIFFICULT QUESTION
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Answered by
11
Let the numbers be ab and xy, where a and x are the tenth place digits and b and y are the oneth place digits.
ab * xy = 1998
ax = 15
Only 5 and 3 are single digit numbers that yield the result 15
by = 28
Only 7 and 4 are single digit numbers that yield the result 28.
The units have to 7 and 4 and the tenth place digits are 5 and 3.
so the number is 57 * 34 or 37 *54
Of theise only 37 * 54 = 1998.
Therefore, the two numbers are 37 and 54.
ab * xy = 1998
ax = 15
Only 5 and 3 are single digit numbers that yield the result 15
by = 28
Only 7 and 4 are single digit numbers that yield the result 28.
The units have to 7 and 4 and the tenth place digits are 5 and 3.
so the number is 57 * 34 or 37 *54
Of theise only 37 * 54 = 1998.
Therefore, the two numbers are 37 and 54.
Answered by
5
answer is 37 and 54
15 only 5 and 3 single digit number 5×3=15
1998 only 37 and 54 are single digit number ok
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