Math, asked by kundanrazz20161, 6 months ago

the product of two 2-digit number is 1998 . If the product of their units digits is 28 and that of tens digits is 15 , find the number .


PLEASE ANSWER IN FULL FROM ...,,,, THIS IS VERY DIFFICULT QUESTION

Answers

Answered by nakul2006
11
Let the numbers be ab and xy, where a and x are the tenth place digits and b and y are the oneth place digits.

ab * xy = 1998

ax = 15

Only 5 and 3 are single digit numbers that yield the result 15

by = 28

Only 7 and 4 are single digit numbers that yield the result 28.

The units have to 7 and 4 and the tenth place digits are 5 and 3.

so the number is 57 * 34 or 37 *54

Of theise only 37 * 54 = 1998.

Therefore, the two numbers are 37 and 54.
Answered by gamerkrishna438
5

answer is 37 and 54

15 only 5 and 3 single digit number 5×3=15

1998 only 37 and 54 are single digit number ok

pls add me as brainlist

Similar questions